(x-4)^2/3=12

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Solution for (x-4)^2/3=12 equation: 


x in (-oo:+oo)

((x-4)^2)/3 = 12 // - 12

((x-4)^2)/3-12 = 0

((x-4)^2)/3+(-12*3)/3 = 0

(x-4)^2-12*3 = 0

x^2-8*x-20 = 0

x^2-8*x-20 = 0

x^2-8*x-20 = 0

DELTA = (-8)^2-(-20*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)+8)/(1*2) or x = (8-144^(1/2))/(1*2)

x = 10 or x = -2

(x+2)*(x-10) = 0

((x+2)*(x-10))/3 = 0

((x+2)*(x-10))/3 = 0 // * 3

(x+2)*(x-10) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-10 )

x-10 = 0 // + 10

x = 10

x in { -2, 10 }

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